6. ATOMIC, NUCLEAR AND QUANTUM PHYSICS
ATOMIC AND QUANTUM PHYSICS
(SECTIONS 6.1 - 6.7)
6.1. The atomic model
During the 1800s the idea that all materia
consists of atoms gradually gained support. Its fundamental particles are, as we
today describe it, the electrically positive proton (p+) and neutral
neutron (n) which both are ca 2000 times heavier than the negative electron (e-).
The electrons occupy certain levels or "shells" outside the nucleus
with the protons and neutrons.

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Evidence for the idea that the positive charges
in the atom are not spread evenly in it (the Thomson model) is given by the
Geiger-Marsden (or Rutherford) experiment in which positive particles (alpha
particles from decaying atoms, see later) are aimed at a thin gold foil. The
result is that most of them pass through the foil without changing direction,
while some bounce back in almost the same direction as they came from. This can
be compared to firing a machine gun at a fence made of solid iron bars with
wide openings between them, as opposed to firing it against a wooden fence with
no openings.
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The radius of an atomic nucleus can be found by
letting positive particles with a known kinetic energy be scattered (bounce
from) the nuclei. The "closest approach" is found by equating their
kinetic energy with the electrical potential difference they need to overcome:

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·
Kinetic energy : Ek
·
Potential far from nucleus: V1 = - kqnucleus / r1,
where r1 >> 0 and V1 » 0.
·
Potential at closest approach distance from center of nucleus = V2 =
- kqnucleus / r2, where r2 = rnucleus
.
·
Potential difference = V1 - V2 = kqnucleus / rnucleus
Work done against repulsive electrical field of
nucleus = Ek = qparticleDV = k qparticle qnucleus
/ rnucleus
=> rnucleus = Ö (k qparticle qnucleus /
Ek )
It can be found that the radius of the nucleus
is far smaller (ca 10-14m) than the size of the whole atom (10-10m)
which therefore can be compared to a solar system with a central body
(sun/nucleus), smaller bodies around it (planets/electrons) and nothing in
between. Other experiments (Thomson and Millikan) showed that the mass of the
electron is much smaller (ca 1/2000 of) than that of a hydrogen nucleus. The
discovery that the nucleus besides positive charges (protons) also contains
neutrons will be returned to later (mass spectrometer section).
6.2. Spectra and energy levels in atoms
Emission spectra
If a small amount of a pure gas is placed in an
airtight tube and this tube is heated e.g. by letting an electric current pass
through it, it will emit some light. If this light is led through collimators
and a diffracting prism the wavelenghts of light present can be studied. Unlike
white light (or sunlight) only certain wavelengths will be present
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Absorption spectra
If white light with all wavelengths present
passes through the gas in the tube, most of it will pass through but some
wavelengths will be missing - the same ones as were emitted from the heated
gas!

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An interpretation of this is the following:
·
the electrons in atoms can be in certain "shells" numbered n = 1,2,3,
.. or indicated with letters K, L, M, N, ... (K =1 , L = 2 etc)
·
when and electron falls from a higher to a lower level, the difference in
energy between the shells can be sent out as a photon
·
photon = "particle" of light or other electromagnetic radiation. The
energy of the photon is:
·
in an emission spectrum : since there are only certain possibilities to
fall in an atom (shell 2 -> 1, 3 -> 1, 4 -> 1 , ..., 3 - >2, 4
-> 2, ...) only certain frequencies are emitted, and these are typical for a
certain element)
·
the "falls" can be called Ka, Kb, ..., La, Lb, ... where the letter says to which
shell an electron falls, and a that it falls from the next higher,
b from one two shells higher etc. For example Lb means it falls to shell 2 from shell 4.
·
the higher the energy difference between the shells (can be illustrated as an energy
level diagram) the higher the energy of the photon and the higher the
frequency or the lower the wavelength of the emitted light.
·
absorption spectrum : if white light with all possible wavelengths
present passes through a vapour of an element, the photons will be absorbed, =
disappear and turn to energy lifting an electron to a higher shell (from which
it probably will fall back down later). Then the frequencies which would have
been emitted in falling are now missing from the spectrum.

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It can be shown [Planck's studies of blackbody
or cavity radiation (not in the IB), supported by the photoelectric effect
(later)] that the energy of a photon, a "particle" of light is
E = hf [DB
p. 8]
where f = the frequency of the light or other
EM waves, and h = Planck's constant = 6.63 x 10-34 Js
Since the speed of light = c = fl = constant in vacuum = 300 000 000 ms-1
we also get f = c/l and
E = hc/l
The empirical Rydberg formula
For hydrogen atoms it was found experimentally
that the wavelength l of the emitted light follows
1/l = RH(1/n2 -
1/m2) [DB p 11]
where n = the number of the shell the electron
falls to, m = number it falls from and RH = the Rydberg constant = 1.096
x 107 m-1 (not the gas constant R, not in data booklet,
given when needed).
Example: What frequency is emitted by hydrogen in a Lg emission?
Solution : Lg means the electron falls to shell 2
from shell 5 so
1/l = R(1/22 - 1/52)
= R(1/4 - 1/25) = 0.21R => l = 1/0.21R = 1/(0.21 x 1.096 x 107 m-1) =
4.3448 x 10-10 m and since c = fl => f = c/l we get
f = 300 000 000 ms-1 / 4.3448 x 10-10 m = 6.9 x 1017
Hz
6.3. The Bohr model of the atom
Bohr's assumption
Earlier the Rutherford experiment (also called Geiger-Marsden
experiment) had shown that most mass in the atom is in the positive nucleus.
But electrons orbiting the nucleus should be sending out radiation (since they
are accelerated, according to theory not in the IB programme) and then lose
energy and collapse into the nucleus. This does not happen, and Bohr assumed
the following:
·
only certain orbits with certain radius values are allowed and in these the
electron is stable
·
the smallest value, r1 for shell n = 1 (the K-shell) is the
"ground state". If an electron is higher up and there would be room
for it in a lower shell, it is in an "excited" state.
·
the allowed radius values are such that the angular or rotational momentum L is
mvrn = nh/2p = nh' [not in DB]
where m = mass of electron, v = speed of
electron, n = shell number, h = Planck constant.
[It can then be shown that the same formula for
the emitted wavelength as Rydberg found experimentally is true:
First, for
the possible radii of the orbits of electrons in an H-atom where the nucleus
and the electron have the same charge q (=e) though with opposite signs:
·
the centripetal force on an electron = the Coulomb force so mv2/r =
kqq/r2 = kq2/r2 where k = the Coulomb constant
·
solving for r gives r = kq2/mv2 and using mvr =
nh' with h' = h/2p which gives v = nh'/mr we
get:
·
r = kq2/(m(nh'/mr)2) which becomes r = kq2mr2/n2h'2,
solving for r gives:
·
r = h'2n2/(mkq2) or for shell n : rn
= constant A * n2
Then to
find the energy levels we note that an electron, like a satellite in orbit
around a planet, has both a kinetic and a potential energy which is negative:
·
E = Ek + Ep = ½mv2 + (- kqq/r) = ½mv2
- kq2/r into which we put v = nh'/mr so
·
E = ½m(nh'/mr)2 - kq2/r = (n2h'2/2mr2)
- kq2/r and using r = h'2n2/[mkq2]
then
·
E = (n2h'2/2m(h'2n2/[mkq2])2)
- ( kq2/(h'2n2/[mkq2]) )
which will give
·
E = - mk2q4/2h'2n2 or for shell n :
En = - constant B / n2
·
here we have const.B = mk2q4/2h'2
For n = 1
it turns out that E = - 13.6 electronvolts, the energy needed to ionise a
hydrogen atom with its electron originally in the lowest shell. To get towards the
Rydberg formula we look at an electron falling from shell m to shell n (or
being raised from n to m), where m > n :
·
the change in energy = En - Em = -constB/n2 - (-constB/m2)
which is
·
constB (1/m2 - 1/n2). When the atom loses this energy, a
photon with the energy E = hf is emitted. The change in energy of the atom is
negative and that of the photon is positive (so totally the energy is
conserved). We can equate them after adjusting the sign:
·
- hf = constB*(1/m2 - 1/n2) or hf = constB*(1/n2
- 1/m2). Combining with c = fl giving hf = hc/l we then have:
·
hc/l = const.B*(1/n2 - 1/m2)
or dividing with hc then
· 1/l = (const.B/hc)*(1/n2 - 1/m2)
Finally we
note that:
·
(const.B/hc) = (mk2q4/2h'2)/hc. Inserting the
values gives the same value for this expression as that of the experimentally
found Rydberg constant RH. ]
The limitations of the Bohr model are:
· why
do the electrons stay in their orbits - they are centripetally accelerated and
should emit energy, and lose potential energy and collapse into the nucleus?
· why
should the assumption about the rotational momentum be made?
6.4. De Broglie and materia as waves and
particles ("dualism")
But why would mvrn = nh/2p? The answer is in looking at all material (in
this case electrons) as being a particle and and a wave at the same time
(earlier we have defined light as waves and "photon" particles at the
same time - more support for this later).
The double slit experiment
A reason for looking at electron as waves is
that if they are sent towards two or more very narrow slits they do not just
end up right behind the slits but bend to the same directions as laser light
would in a Young's experiment (remember the d sinq = nl formula!).
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De Broglie assumed that the electron (and all
other particles) would at the same time be waves with the wavelength
l = h/p [DB
p. 8]
where h = Planck's constant and p = the
momentum = mv
[The reason for this is the theory of
relativity, which says that for the total energy E of something E2 =
m02c4 +p2c2 which for
massless photons becomes E2 = p2c2 or E = pc
which with the photon energy E = hf = gives pc = hc/l so p = h/l or l = h/p.
Assuming that the same is true for electrons in
the double slit experiment gives a l which fits the usual d sinq = nl formula.]
Electrons as standing (stationary) waves around
the nucleus
A wave can exist for a longer time in a certain
place if it is a standing wave, like that on a guitar string. In an atom where
no air resistance or friction damps it, it can remain standing
"forever". An electron wave must be bent around the nucleus:

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To fit in the electron wave must follow the
condition nl = 2pr => nh/p = 2pr => nh/mv = 2pr => mvr = nh/2p which was Bohr's assumption (originally made
only because it happened to lead to a formula which fits Rydberg's
experiments).
6.5. The Schrödinger model of the atom
From de Broglie waves to the wavefunction Y (psi)
Above we have desrcribed particles, like an
electron, with waves as in the de Broglie wavelength l = h/p. In this we use one concept
relevant to waves (wavelength) to give information about one quantity relevant
to the particle (momentum). In modern quantum physics, this has been extended
so that a "wave function" Y is used to describe the particle.
The equation for an ordinary travelling wave can be written (with A =
amplitude) for example as y(t) = Asin(2pft + phase shift) or y(x) = Asin(2px/l + phase shift). In the wave function
sine and cosine functions are also used, but the variable and also the function
can have imaginary or complex values (of the form a +bi, where a and b are real
numbers and i the imaginary number unit, where by definition i2 =
-1). The wave function can be very complicated but for a particle moving in one
dimension along the x-axis it can be something like
Y(x) = cos(kx) + i sin(kx) = eikx
where k = the wave number = 1/l. The complex numbers mean that it is difficult
to describe where a particle is directly with the wave function, since a
probability should be a positive real number. What is used instead is the
square of the absolute value of it. If we focus on one dimension, the
probability of finding the particle in the interval Dx of the x-axis will be:
probability of x being
in Dx at the time t = ½Y(x,t)½2 Dx
which was under the assumption that Y has a constant value in this interval, which
rarely is true. One will then use an infinitely short interval dx where the
probability is ½Y(x,t)½2 dx
Since the particle with a probability of 100% =
1 is somewhere on the x-axis (in the one-dimensional case) summing up all the
probabilites from all small intervals from negative infinity to positive
infinity will be = 1. If it isn't, the wave function can be renormalised
by introducing a suitable constant into it. Then we will have (for a sum of
infinitely many infinitely small intervals)
+¥
ò½Y(x,t)½2 dx = 1
-¥
Quantities as operators
A function is something that transforms one
number into another, for example the function y = x2 turns 1 into 1,
2 into 4, 3 into 9, 4 into 16 etc. An operator is something which transforms
one function into another function. The integral and derivative are operators;
for example the operator derivative transforms y = x2 into y' = 2x.
But there can be many other operators (although many of them do contain some
kind of derivatives) and most physical quantities can be represented by
operators operating on the wave function. For example the quantity momentum
will (in one dimension, the x dimension) be:
p = ih'd/dx
(that is, the x-derivative multiplied by ih/2p using h' = h/2p. In most books h' would be
symbolised by an h with a bar through its vertical part, an called "h
bar").
The Hamilton (total energy) function and
operator
The most important operator is the one which
describes the total energy of a particle and therefore can be used to give as
much information as possible about the particle and its future. Classically,
the Hamilton function is
H = Etot = Ek + Ep
which also can be written (since p2/2m
= m2v2/2m = ½mv2 = Ek)
H = p2/2m + V or better: H = p2/2m
+ Ep
where the "V" is often called
potential (and may change both with place and time) although this is not very
good since it cannot be a potential (unit Jkg-1) and still added to
an energy (unit J). In this section V is then used as another symbol for Ep,
unlike in the Mechanics where it was V = Ep/m or the Electricity
sections where V = Ep/q. We can note that in the p2/2m-term
m is the inertial mass while the V stands for any potential energy,
related to gravitational force, electrical force or other (e.g. strong
interaction or a combination of several forces). Compare this to the difference
between inertial and gravitational mass.
As an operator p2/2m then becomes
(-h'2/2m)d2/dx2 and the whole Hamilton
operator then
H = (-h'2/2m)d2/dx2
+ Ep(x,t)
The Schrödinger equation
A differential equation is one where functions
and their derivatives (and possibly other things, like various constants) are included.
The solutions to differential equations are functions which satisfy them.
All that can be known about a particle is
expressed in the Schrödinger equation, which is a differential equation:
ih'(dY/dt) = HY or
ih'(dY/dt) = (-h'2/2m)d2Y/dx2 + Ep(x,t) [not in DB]
The Schrödinger equation in one dimension can
use either only a function of the position of the particle Y(x) - the time-independent Schrödinger function
- or of both the position and the time Y(x,t) - the time-dependent function,
which describes all that can be known about the particle now and in the future.
In 3 dimensions we have Y(x,y,z) and Y(x,y,x,t).
The collapsing wave function
When a measurement of a physical quantity is
done (for example momentum) then the operator O associated with this quantity
will produce a function v(x,t) for value of the quantity where so that
OY(x,t) = v(x,t)Y(x,t)
This is a differential equation and the
solution is a function which gives the value of the quantity. If the
measurement is never done in a certain chosen way, the quantity does not have a
well-defined value. Since the wave function can contain terms that represent
interference - constructive of destructive - the "particle" can
behave in a wave-like way (for example a single electron passing through both
slits in a double-slit experiment and interfering with itself to produce a
pattern similar to that in a Young's experiment for light). Measuring it and thereby letting it
"get" a more defined value (e.g. putting an electron detector where
the electrons hit a screen) means is called a "collapsing" of the
wave function. Finding out what can be found out about the value of a physical
quantity would then involve these steps:
·
finding the Ep-function relevant to the situation, and with that the
relevant Hamilton operator
·
solving the Schrödinger equation (a diff. equation); result: the relevant Y-function
·
solving the diff. eq. OY = vY for the operator for the physical
quantity to find the function v(x,t)
·
inserting the relevant x- (and t-, if relevant) values in v(x,t) to find the
value (or calculating the value of ò½Y(x,t)½2 dx
integrating over the relevant interval to find the probability that the
particle is there, that is in the interval dx).
In 3 dimensions we have x,y,z or some other
3-dimensional coordinates instead of just x.
The philosophical question : whether we know or
what we know?
Before the wave function Y has been used to find a probability or other
value, this value is not well defined and some would say that it does not have a
value until we decide to measure it in a certain way (where the way we decide
to measure it will affect what value it gets). One interpretation of this is
that our conscience "produces" the measurement result. It must,
however, be noted that this does not affect the Schrödinger equation itself -
it has the properties it has regardless of our decisions and even existence.
One can therefore say that quantum physics has not changed the answer to the
question of whether we can know things about the world which are
independent of our choices, it has changed the answer to another question: What,
independent of our choices, can we know?
The answer is no longer the values of physical quantities but the
Schrödinger equation.
The Heisenberg uncertainty relations
Measuring two quantities at the same time
cannot always be done with as high accuracy as wanted. In quantum physics this
is not only because of practical difficulties in the measurement but it can be mathematically
shown that certain pairs of quantities cannot be known precisely at the
same time. (Quantities => operators and other relevant concepts can also be
represented by matrices, mathematical tools which in some ways can be
used in a way similar to numbers, but have certain strange properties. The
matrices A and B can be multiplied with each other, but unlike for numbers the
order of multiplication makes a difference: AB is generally not the same as BA
and AB - BA is not zero).
There are many such pairs, but the ones most
often mentioned are:
·
position and momentum
·
energy and time
DxDp ³ h / 2p, DEDt ³ h / 2p [DB
p. 11]
From the latter we get DEDt ³ h / 2p = h' => Dt ³ DE / h'. It turns out that if no measurement-technical difficulties are
in the way the uncertainty is close to its lowest limit, so
Dt » h' / DE = h' / (Dmc2)
The virtual ("Cinderella") particles
The impossibility of knowing the energy of
something is relevant also for the law of conservation of energy - that you
cannot get energy (or mass as in E = mc2) from nothing. This will
have a relevance for the virtual field particles which can "pop
into existence" from nothing, pure vacuum, for a certain time which
depends on their mass. If they are massless they can do so forever and then the
force they are related to can act over infinitely long distances (they cannot
move faster than light). If they have a mass, Dt is limited and the virtual field particle must disappear (like
Cinderella before midnight) and therefore the related force can only act over a
limited, usually very short distance. All the cheated "energy from
nothing" must disappear so the virtual particle cannot be detected since
that would mean some interaction with real particles which might get some of
that energy in this interaction.
The H-atom and spherical coordinates =>
electron shells and subshells
For the electron in hydrogen atoms (and ions
with only one electron left) the Schrödinger equation can be solved
algebraically; for other cases, only numerical approximations with computers
are possible. We will have Y(x,y,z) replaced by another wave
function of spherical coordinates Y(r,q,j) where
·
r = the distance from (the center of) the nucleus
·
q,j = angular coordinates
The angular coordinates can be compared to
longitude and latitude coordinates on the surface of earth (for all points on the
surface r = the radius of earth; the origin of the coordinate system would be
in the center of the earth).
It turns out that the Y-function can be separated as Y(r,q,j) = f1(r)f2(q)f3(j) and the three functions solved
separately. Each gives solutions (involving sines or cosines, which are
functions that can produce a set of discrete solutions, e.g. sin x = 0 gives x
= n*2π, n = 0,1,2,...) for certain whole numbers of a variable (1, 2, 3,
...) like the resonant frequencies of a standing wave in the Waves
section, or the de Broglie description of the electron as a standing wave
around the nucleus.
These discrete values (values that do not vary
continously but only can have certain values) can be used to define several
different quantum numbers for the possible states of the electron. The
most known are the ones given by the solutions involving f1(r) which
give the main or radial quantum number n = 1, 2, 3, ... = "the number
of the electron shell". Other quantum numbers (there is also a fourth
caused by the possibility for the electron to spin either the same or the
opposite way as the nucleus) produce subshells (1s, 2s, 2p, etc.).
6.6. The photoelectric effect
Additional support for E = hf
Planck had suggested that photons could be
described not only as waves but as wave packages or particles with the energy E
=hf. Einsteins explanation of the experimental results for the
"photoelectric effect" support this.
Thermionic emission and basic photoelectric
effect
If we have two metal plates (electrodes) in a
vacuum tube, and connect a voltage to the plates, then some electrons will flow
from the negative cathode to the positive anode. The reason is that at a
temperature above 0 K all electrons have some kinetic energy; some of them
enough to break free from the metal and then be accelerated by the electric
field. If a plate is hit by light, then the electrons get more kinetic energy,
and the current increases.
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Reversing the voltage
To investigate the kinetic energy that the
electrons get we can reverse the voltage (=> we have a "stopping
voltage") or potential difference so that it works against the
electrons which then can get from one electrode to the other only because of
their kinetic energy. Some of this kinetic energy is needed to break the
electron free from the metal, the rest is lost to work against the stopping
voltage. We also let light hit only one of the plates so that we do not get the
same phenomenon working both ways, which would cancel out any current between
the plates. By measuring the stopping voltage needed to get the current to
zero, we can measure the maximum kinetic energy any electron gets from the
light. This, presumably is the energy the light itself has.
a06b
We then have that qVstop
=eVstop = eVs =
½mvmax2 = Ek,max (= KEmax in some books) and can study the phenomenon
either
A. as a function of the frequency of the light (different
colours)
B.
as a function of the intensity of the light (bright or dim light)
Results of A:
·
The graph is a straight line which hits the f-axis at some minimum f0
·
the slope of the line is h = Planck's constant
·
the intercept with the E-axis is always the same, called W0, for the
same metal in the plate hit by the light
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Results of B:
·
Increasing the intensity of the light does not affect either h, f0
or W0
Interpretation : the energy of the light
depends only on h and f, not on its brightness which it should if it was only a
wave. (For a wave the energy transported through a certain area depends on the
amplitude, that is how bright the light is. Here we will then have to
reinterpret brightness of light as number of photons moving per time).
The graph gives the equation Ek,max
= hf + W0 if W0 is negative or Ek,max = hf - W0
if we keep the value positive.(Compare this to a graph of y = 3x - 2 which has
the slope 3 and intersects the y-axis at -2). Moving terms we get hf = W0
+ Ek,max or if we as the IB:s data booklet use φ as a symbol for W0:
hf = φ + Ek,max [DB p. 8]
or since eVs = Ek,max we
get hf = φ + eVs and if by f0 we mean the frequency
value at which the graph intersects the horisontal f-axis, that is where Ek,max
= 0, then inserting this in hf = φ
+ Ek,max gives hf0 = φ so the same formula can be written:
hf = hf0 + eVs [DB p.8]
where W0 or φ = the
"work function" = the energy or work needed to free an electron
from the metal (different for different metals).
6.7. X-rays
X-ray production and spectral features
When electrons are accelerated from a negative
cathode (which may be heated to increase the number electrons which break away
from the cathode) towards a positive anode by a high voltage V (several
kilovolts) they will hit the target atoms and either:
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·A:release all
or part of its kinetic energy as a radiated photon during the deceleration
("Bremsstrahlung"), which is based on the notion that accelerating
charges means they lose energy (same as the problem with the Bohr model, where
the centripetal acceleration should make them lose energy) or
· B: strike out an electron from an
inner shell even if there are several electron shells in the atom. When an
electron from a higher shell falls down to replace it, photons with certain
high energy values are released.
The highest energy E = hf with the highest f
and the lowest l since E = hc/l (so that energy and wavelength are inversely
proportional to each other - minimum
wavelength corresponds to maximum energy!) is obtained when all the work by
the accelerating voltage = qV = eV becomes kinetic energy ½mv2 and
then photon energy hc/l = eV => l = hc/eV, the shortest emitted l:
lmin = hc/eV
The important features of the X-ray spectrum
are then:
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1. the minimum of cutoff wavelength, which can be decreased by
increasing the accelerating voltage V
2. the continuous curve (from A) of X-ray intensity for
electrons which give only part of their kinetic energy to radiation of photons
(the rest to absorptions related to energy levels which produce other radiation
than X-rays)
3. the characteristic peaks from (B) the strikeout electrons
replaced by others falling down (the higher the difference between the energy
levels of the involved shells, the higher the photon energy => the lower the
l, so a Ka- peak would be to the right of a Kb-peak since the latter gives more energy)
[X-ray diffraction in a crystal lattice
Waves with short wavelengths can be diffracted
by the atoms in a crystal lattice (Sw. kristallgitter, Fi. kristallihila) as in
the graph below.
a07c
Note that the angle used is the grazing
angle = the angle between incoming ray and surface, not incoming ray and
normal to the surface as usual. For this the Bragg formula: 2dsinq = nl is valid and l = h/p makes it work also for electrons.]
NUCLEAR AND PARTICLE PHYSICS (SECTIONS 6.8 -
6.19)
6.8. The mass spectrometer and evidence for
nuclides
If atoms are ionised by heating or other they can
be accelerated by a potential difference. If they are then entering a
homogenous magnetic field there will be a magnetic force acting as a
centripetal force on them when they move in a circular path. The radius of the
circle (or here, half circle) will depend on their mass and velocity:

a08a
which gives
qvB = mv2/r => m = qBr/v. If ions of the same
element are used and the velocity of them when entering the magnetic field is
the same then any difference in radius must be caused by differences in mass
between nuclei of the same element. To arrange this we use a mass
spectrometer:
a08b
1. Ion source (e.g. gas heated enough to be ionised) with accelerating voltage Vacc . Charges
(ions) q are accelerated by an electric
field Eacc. In this acceleration they get a velocity given by ½mv2
= qV where V = the potential difference used.
2. Speed filter : This velocity can be controlled even more
precisely by letting them into a chamber where we have a crossed electric field E and a magnetic field B;
here E from up to down in the plane of the paper and B out of the plane of the
paper causing force which for charges q with a suitable velocity v cause
opposite forces of equal magnitude:
·
Felectric = Fmagnetic where E = Felectric/q
=> Felectric = qE
·
qE = qvB which cancelling q gives
·
v = E/B
With collimators (two or more narrow slits or
holes that the charges must pas through) only ions with precisely the right
velocity v can pass into the
3. Separation chamber : here the charges enter another
magnetic field B' but not electric field, so the magnetic force can act as a
centripetal force giving
·
mv2/r = qvB' and as before
·
m = qBr/v which with v = E/B giving
·
m = qBB'r/E
By letting the ions move in a half-circle with
radius r in the separation chamber they will hit a detection device
(photographic film or other) in slightly different places if they have
different masses. This can be used to find the precise mass of an ion and is
used in organic chemistry to help find out the properties of unknown moleculse;
it has also been used to separate heavier 238U - versions (isotopes)
of uranium from lighter 235U which can be used for nuclear fuel or
weapons. (More effective methods based on gas diffusion are more common today).
6.9. The nucleus
Atom number Z and mass number A
With a mass spectrometer it can be shown that
nuclei of the same chemical element can have different masses. Since this
cannot be caused by different numbers of protons (which would result in a
different number of electrons and therefore other chemical properties for the
neutral atom) there must also be neutral particles in the nucleus. These are
difficult to detect directly since most detection methods are based on the
electric charge of a particle, but indirectly (detecting not the neutrons
themselves but particles resulting from nuclear reactions caused by neutrons)
neutrons were discovered in 1930.
·
nuclide = proton or neutron
·
isotope = versions of nuclei of the same element with the same number of
protons but different numbers of neutrons
An atom of the element X with the atom number Z
(= number of protons = number of electrons if neutral) can be symbolised:
AZX
where A = the mass number = the total number of
protons (Z) and neutrons (N) so A = Z + N. Example:
23892U (or before: U-238)
means a uranium atom with 92 protons (as all
uranium atoms have) and a total of 238 nucleons, so the number of neutrons is
238-92 = 146.
The unified mass unit
The mass of a nucleus is small and here often
measured in the "atomic mass unit" where 1 u = 1.66 x 10-27
kg (by definition 1/12 the mass of a C-atom). The masses of various particles
and atoms (usually the mass not for the nucleus alone but for the neutral atom
including Z electrons) is found in various tables. Examples:
electron e 0.000549
u
neutron n 1.008665
u
proton p 1.007276
u
1H - atom 1.007825
u
4He - atom 4.002602
u
12C - atom 12.00000
u (by definition)
16O - atom 15.994915
u
Keeping
the nucleus together: electric repulsion and strong interaction
In the nucleus we have positive charges which
with the electric Coumolb force would repel each other and would make the
nucleus split unless another force, the "nuclear force" or strong
interaction kept it together. There are 4 basic forces or types of interaction:
·
gravity
·
electromagnetic
·
strong interaction ("nuclear force")
·
weak interaction (causes some types of radioactive decay)
The nuclear force is attractive at distances about
the size of a nucleon and thereafter very quckly becomes weaker (so for larger
nuclei one tends to need more and more nucleons to keep it stable; in He, C and
O the stable isotopes have Z = N but in uranium Z = 92 and N = 146!). At
distances shorter than the size of a nucleon it becomes repulsive, preventing
the universe from collapsing.
6.10. Mass defect and binding energy
Mass defect and mass as a form of energy
Mass defect (missing mass): if we add the mass of the constiuents and
compare it to the mass of the whole neutral atom (including electrons), then
some mass is missing.
Ex. for 42He
the mass is 4.002602 u but if we add up
2me + 2mp + 2mn
= 4.032982 u then some mass is missing; the difference is
4.032982 u - 4.002602 u = 0.03038 u
According to relativity theory (later), mass
and energy are two forms of the same thing. They follow:
E = mc2
where c = the speed of light.
Mass can then also be measured in energy units,
like the electronvolt. 1 u = 931.5 MeV (data booklet).
This missing mass is then a form of energy
which may be released if the atom and especially the nucleus changes in such a
way that more energy is missing. The missing energy can be called binding
energy. It is usually calculated positive, although it could (maybe more
reasonably) be given a negative sign, like the negative gravitational potential
energy of an object near a planet. This can happen both in radiactive decay and
nuclear fission and fusion (described later) all of which can produce heat
energy.
6.11. Changing the nucleus I : natural
radioactivity
In a nucleus, the repulsion between the
positive protons is overcome by the nuclear force or strong interaction which
is attractive at suitable distances, see above. This leads to a certain
relation between the number of protons and neutrons being most stable, which
can be described by a graph of the "stable valley":
a11a
Nuclides outside the stable valley may approach
it by radioactive decay, here primarily alpha and beta decay. The
third type of decay, gamma decay, concerns a rearranging of the protons
and neutrons in the nucleus without changing the number of them.
This decay means that a parent nucleus X
is transformed into a daughter nucleus Y and one or more particles (a,
b, ...) emitted. (For gamma decay, X = Y and only a massless photon is
emitted).
X -> Y + a + b + ...
The process can happen spontaneously in nature
if energy is released, that is the mass of whay we have after the decay is less
than we hade before. This energy is taken away as kinetic energy of the Y, a,
b, .... The released energy or reaction energy or "Q-value" is for
the decay X -> Y + a
Q = (mX - mY - ma)c2
This is can happen spontaneously if the Q-value
calculated as above is positive.If it is negative, a decay or other nuclear
reaction may still be caused if a particle is shot at the target nucleus with a
high enough kinetic energy to balance out a negative Q (see artificial
transmutation below).
6.12. Types of radioactive decay
Alpha decay of nucleus X
AZX -> A-4Z-2Y
+ 42He
The helium atom or in practice
positive ion is called alpha particle, sometimes 42a.
Beta decay of nucleus X, type 1: b - -decay
The most common type of beta decay
is b- -decay where electrons
are emitted as a neutron in the X-nucleus turns into a proton and the emitted
electron.
AZX -> AZ+1Y + 0-1e + 00n
where the n indicates an antineutrino (more often symbolised with an overlined nu),
a (probably) massless particle whose existence was postulated since beta decay would
violate the laws of momentum and energy conservation if X only split into Y and
the electron. (What an antiparticle is, and why we think an antineutrino is
emitted here instead of an ordinary neutrino we will return to in particle
physics later).
a12a
That a third particle is emitted
could in principle be discovered by noting that the Y and the electron do not
leave in exactly opposite directions as they should if X was at rest before the
decay but this is difficult to observe since a sample contains millions and
millions of atoms decaying in random directions. It can however be observed
since if only two particles were emitted, any one of them should have a kinetic
energy which depends only on the masses of the two and the energy Q released
(from the difference in mass between the particles before and after the decay).
In reality the emitted electrons have many different ("a continuous
spectrum of") kinetic energies.
Assume we call the Y object 2 and
the emitted electron object one. Conservation of momentum (with X at rest)
gives (primes for situation after, no primes for situation before decay):
· 0 = p1
+ p2 = p1' + p2' so p2' = - p1' and squaring => p2'2
= p1'2
Conservation of energy then gives that
any kinetic energy after the collision equals Q or:
· Ek1'
+ Ek2' = Q which using Ek = p2/2m can be
written
· p1'2/2m1
+ p2'2/2m2 = Q and then using p2'2
= p1'2
· p1'2/2m1
+ p1'2/2m2 = Q, factorise out p1'2
so
· p1'2(1/2m1
+ 1/2m2) = Q
Then make 2m1m2
the common denominator in the parenthesis and we get
· p1'2[(m2
+ m1)/2m1m2] = Q so
· (p1'2/2m1)[(m2
+ m1)/m2] = Q or
· Ek1'[(m2
+ m1)/m2] = Q and finally
· Ek1' = Qm2/(m2
+ m1)
so the kinetic energy of the
electrons emitted should have a constant value for the beta decay of a given
isotope - which they do not, experimentally. (The kinetic energy of the emitted
particles is easier to measure, for example collimators and a magnetic field
should if the kinetic energy was constant make them all move in a circle with a
constant radius, like a mass spectrometer without the speed filter. They do
not.)
Beta decay of nucleus X, type 2 : b + -decay
Another type of beta decay is one
where a positron, the antiparticle of the electron (see particle physics
later) is emitted; a particle with the same mass as the electron but the
opposite electric charge. The third particle emitted here is an ordinary
neutrino, not an antineutrino.
AZX -> AZ-1Y + 0+1e + 00n
Beta decay of nucleus X, type 3 :
Electron capture (EC)
This is a case where the nucleus
snatches an inner-shell electron (whose place is then filled by some electron
higher up falling down, whose place is taken eventually by an electron from the
environment. It may seem worrying to environmentalists that electrons can just
be dumped into or stolen from the environment like that, but due to the
enormous amount of electrons which exist in nature this is not a significant
threat to biodiversity. It may comfort the reader to know that this file was
generated using 100% recycled electrons). An ordinary neutrino, not an
antineutrino, is also emitted.
AZX + 0-1e
-> AZ-1Y + 00n
Gamma decay of X
Here no particle other than a photon
with very high energy E = hf is sent out. This can happen if the nucleus was
excited, that is the nucleons not arranged as close to each other as possible,
so they can release energy by "falling" closer to each other. That
the nucleus X has some of its parts in a higher energy state than the lowest
possible - that it is "excited" - is denoted with the symbol X*.
AZX* -> AZX
+ photon
The high energy and therefore high-frequency electron
(or low-wavelength photon) has a higher frequency than X-rays.
Other decays of X
Besides alpha, beta and gamma decay there are
other types of decay, most notably those where neutrons are emitted and those
were "particles" larger than an alpha particle are emitted
("cluster radioactivity").
6.13. Nuclear energy levels
Inside a nucleus we have protons and and
neutrons which are arranged in a structure not entirely known yet. It seems
that some "chunks" of nucleons are more stable thant others, namely
those with "magic numbers" for Z or N = 2, 8, 20, 28, 50, 82 or 126.
For example helium has Z = N = 2 (and A = 4) wherefore the helium nucleus or
alpha particle is very stable. It may be possible to think of nuclei as
consisting of these "chunks" arranged in some way, for example to
think of some chunks orbiting others or other more or less stable parts of a
nucleus. This structure is relevant only at a the nuclear level - for the
outside world, e.g. the electrons in the atom or another atom the nucleus is
one concentrated object.
a13a
We may then consider these "orbits"
(or other features of the internal structure of the nucleus) to be quantized like the orbits of the
electrons around the whole nucleus. They would have discrete energy levels,
not continous ones. Experimental support for this is:
·
alpha particles emitted in decay only have certain discrete
(kinetic) energies
·
gamma spectra are also discrete, like the atomic spectra (of visible
light, IR or UV) emitted when electrons fall between electron shells (maybe a
chunk has fallen down to a lower orbit)
For this reason the (not yet complete) model of
nuclear structue is called a "shell" model of the nucleus.
6.14. Effects and detection of radiation
Ionising radiation
Particles emitted in radioactive decay
primarily affect matter by ionising the atoms of the target material. Alpha and
beta particles are themselves electrically charged, gamma radiation can cause
secondary beta radiation (electrons) by giving part of its energy to an
electron and being scattered with a lower remaining energy and therefore
frequency (a phenomenon called Compton scattering, not in the IB programme).
The same ionising of materia hit by radiation
is used in detecting it; for gamma radiation other methods than those mentioned
here are used (certain materials, such as tellurium-treated sodium iodide emit
visible light after being hit by gamma and this faint light can be magnified
with a photomultiplier).
The G-M tube
The Geiger-Müller tube consists of a
cylinder-shaped cathode connected to the negative terminal of a rather high
DC-voltage source, and inside it a positive anode wire. In the tube there is a
gas (argon) at low pressure. When a charged particle passes it, some gas atoms
are ionised and moved by the electric potential difference causing a weak
current pulse which is amplified and fed to a loudspeaker and/or analogue
indicator.
a14a
The ionization chamber
This older and more primitive device in which
the charged alpha or beta particles themselves are to be electrically attracted
to the electrodes causing a current pulse.
[Cloud and bubble chambers
Especially in particle physics, charged
particles may also be detected by the track they leave in vapour about to
condense into a liquid (compare to tracks in the air left by airplanes or
Formula 1 racing cars) or the track of bubbles in a liquid about to start
boiling. Photographs of these tracks may show circular paths of cloud or bubble
tracks if a magnetic field is applied; the radius of such a circle gives
information about the energy of the particle.]
6.15. Decay calculations and
half-life
Radioactive decay formulas
Decay is a random process where we cannot
say exactly when one atoms splits, only the probability that it does in a
certain time, for example one second.
The decay can be described with
DN = - lNDt
where N = the number of suitable
nuclei, Dt the time period and l = the decay probability (NOT
any wavelength!). The minus shows that the number of nuclei of this type
decreases as a result of the decay into something else.
It can be shown (mathematically: a
differential equation where we have dN =
-lNdt so dN/dt = -lN, compare this to y'(x) = ky(x),
with the solution y(x) = ekx) that if we start with N0
nuclei at the time t = 0 the number of nuclei left =N after a time t is
N = N0e-lt [DB p.8]
where e now means the Napier's
number e = 2.718....
For the activity = the number of
decays per second = A = DN/Dt we also have
A = A0e-lt
The unit of activity = 1 decay/second
= 1s-1 = 1 becquerel = 1 Bq
Half-life
For the time it takes to go from N
= N/2 we have N/2 = Ne-lt => 1/2 = e-lt
=> 2 = elt which if we take the
natural logarithm (the inverse function to ex) of both sides gives
ln 2 = lnelt =>ln 2 = lt => t = ln 2 / l
This time is called the half-life
:
T½ = ln 2 / l [DB
p.8]
Measuring the half-life of a nuclide
With a detector like a GM-tube we
can get information about the activity as a function of time for a radioactive
sample. It should be an exponentially decreasing curve, and the half-life can
be found by taking any point on the curve, reading its activity value, and
moving to the right on the horisontal time axis until half the first activity
value is found. The time moved is the half-life. (Note that the shape of this
curve is independent of the initial number of nuclei, and the half-life of how
many % of the decays the GM-tube registers).
a15a
Alternatively, we can plot ln A as
a function of t:
· A = A0e-lt , taking natural
logarithms gives
· ln A = ln(A0e-lt) = ln A0 + ln(e-lt) = ln A0 + (-lt) so
· ln A = -lt + ln A0 , that is we
get a straight line with the gradient = -l and using the l we find the half-life
from T½ = ln 2 / l
The measurements are problematic if
the unknown half-life is either very long (maybe billions of years) or very
short.
Very long half-lives: We can the the l (and consequently the T½)
from DN = - lNDt
if we know N (the number of radioactive atoms in the sample; this can be found via
chemical calculations of how many moles of the radioactive substance we have)
and DN, the number of atoms
which have decayes in a certain measurement time Dt. This is not the same as the number of ticks heard from the GM-tube
(or other activity measurement apparatus) since it has a low
"efficiency"; that is it gives a tick only for every so many hits. If
this efficiency is found using other samples with a known activity, then the
problem is solved.
Very short half-lives: If the nuclide decays
very quickly it may have to be produced (maybe with artificial transmutation,
see 6.16. below) in the detector rather transported to it. If the decaying atom
(or particle) is formed in a particle accelerator, then the distance it travels
before decaying indicates the "life" of an indiviual atom or
particle; many such measurments give the average half-life.
Decay chains
If X decays into Y which also is
radioactive, this may decay into Z with a new half-life until a stable
(non-radioactive nucleus is reached).
6.16. Changing the nucleus II : artificial
transmutation
In section 6.11 it was described that
spontaneous natural decay can occur if the reaction energy or Q-value is
positive, that is when we have more mass before than after and the decrease in
mass turns into kinetic energy of the pieces left after the decay. A change of
nucleus where the Q-value would be negative can be caused by accelerating a
particle a to a high kinetic energy and letting it collide with the
"target" X, for example as:
X + a -> Y + b
This artifical (induced) transmutation
can be done if
(ma + mX)c2 +
Ek,a > (mY + mb)c2
In this way it is possible to turn lead into
gold and thus fulfil the old dream of the alchemists, but the price of gold
produced in this way would exceed that of ordinary gold.
6.17. Changing the nucleus III : fission and
fusion
Binding energy per nucleon, fission and fusion
If we calculate the lost mass = binding energy
per nucleon for different atoms (in the example with He above we would have divided
the result with 4 and multiplied with 931.5 to get it in MeV per nucleon) we
can make a graph of binding energy per nucleon as a function of mass number.
a17a
From this graph we can suggest two possible
ways to produce energy:
·
fusion (merging together very small nuclei) or fission (splitting
heavy nuclei) gives more missing mass per nucleon
·
the total number of nucleons is the same
·
this means we get more total missing mass
·
this missing mass is converted to energy as E = mc2 and released in
the nuclear reaction
In principle, energy is released also in
natural radioactive decay as kinetic energy (and consequently an increased
temperature in) the products. This energy source is used in some space probes
since it may work for several years without any moving parts that may need
maintenance (the thermal energy is converted to electrical with a thermocouple
which has a low efficiency but no moving parts).
Fission and fusion can supply much larger
amounts of energy since
·
the change in energy/nucleon is larger than in a decay (e.g. emitting an alpha
particle would not move us as far to the left on the A-axis as a fission where
the parent nucleus is split in parts of roughly half the size of the parent)
·
they can be used in chain reactions, where particles emitted in one fission
cause other fissions (for fusion the situation is somewhat different, see
below).
Fusion
In nuclear fusion, two light nuclei are fused
together producing a new one with less binding energy per nucleon than before,
so energy is released. Since the nuclei to be fused are both positive and repel
each other with the electrical Coulomb force they must be given an enormous
kinetic energy to reach each other, wherefore fusion only occurs at very high
temperatures of millions of kelvins. Fusion reactions are the source of energy
in the sun (gravitational contraction of a cloud of hydrogen produced the
temperatures needed to start the fusion process) and are used in "H-bombs"
or thermonuclear devices. In these, the high temperature needed is given by an
igniting nuclear charge of the fission type.
For peaceful production of energy attempts are being made to use either
of these reactions:
· DD-fusion
(deuterium-deuterium): 21H + 21H
-> 42He
· DT-fusion
(deuterium-tritium) 21H + 31H ->
42He + 10n
DT-fusion is easier to use but has the drawback
that supplies of tritium are limited (ca 1000 years?) and that the neutron
radiation causes machinery parts to become radioactive (they only need to be
stored for about a century for this to decay enough). DD-fusion is more
difficult but D can be produced from seawater for millions of years. Note that
unlike the fission reaction below the products cannot be reused to make a chain
reaction; the energy (heat) produced may however be used indirectly to cause
more reactions.
6.18. Fission chain reactions : bombs and power
plants
Nuclear fission chain reactions
Artificial transmutation is possible
for many situations, but requires that a particle enters the nucleus without
losing too much energy to electric repulsion by the nucleus (alpha) or the
electrons (beta). Gamma radiation does not directly affect any A, Z or N values
if absorbed. But neutrons can hit the nucleus more easily, and in some
reactions they are also emitted, e.g.:
23592U + 10n
-> 9038Sr + 14454Xe + 2 10n
Several different reactions take place and only the
average number of new neutrons is interesting, other possible reactions are
e.g.
23592U + 10n -> 9236Kr
+ 14156Ba + 310n and
23592U + 10n -> 8838Sr
+ 13654Xe + 1210n
· The total mass
and atomic numbers are conserved : e.g. 235 +1 = 90 + 144 + 2 x 1 and 92 + 0 =
38 + 54 + 0
· the
reaction produces energy if the total mass decreases:
mass decrease = mbefore
- mafter = mU + mn - mSr - mXe
- 2 mn
Converted to energy, the mass
decrease causes a released energy Q as:
Q = (mbefore - mafter)c2
and the reaction produces energy if Q > 0
· since the
reaction produces two new neutrons, these can be used again to split new
U-nuclei
· these can
then split 4, 8, 16 and so on in an uncontrolled chain reaction (nuclear
explosion)
· a controlled
chain reaction can be obtained if the number of neutrons that on average
can cause a new fission = the multiplication factor =1
a18a
· in a
reactor, some neutrons are lost because they leak out of the reactor (in a
bomb, to make sure enough of them can hit another U-nucleus there must be a bif
enough piece of U, the critical mass) but can be reflected back by
suitable materials (may be other pieces of fuel and or the water coolant)
Moderators and safety
· the neutrons produced in the reaction have
high speeds, but (for reasons not presented here) only slow neutrons can pass
the 238U - nuclei which are 97% of the uranium in a typical reactor
· to make
sure enough neutrons can pass through the 238U and reach a 235U
which is suitable to be split, the neutrons must be slowed down by a moderator
· this is a
material which is made of light nuclei such that when neutrons collide with it,
they are slowed down (compare a billiard ball hitting another)
· if the
moderator and the coolant (the water or other material which transports away
the generated energy as heat) are different materials, the chain reaction can
continue even if the cooling fails or the control rods (which absorb extra
neutrons) fail, which means there is a risk for uncontrolled fission (meltdown)
· if the
moderator and coolant are the same material (technically difficult), a loss of
coolant means a loss of moderator and therefore the chain reaction stops. This
"passive safety" is used in modern reactors.
· the other
products of the reaction (Sr, Xe) absorb neutrons and when enough has formed in
the uranium fuel, the chain reaction cannot continue and the fuel must be
changed.
6.19. Particle physics
Real particles
and virtual field (exchange) particles
Main types (things which exist and things which
do not)
|
REAL
PARTICLES |
VIRTUAL
PARTICLES |
|
|
LEPTONS |
QUARKS
(as hadrons = either baryons or mesons) |
(one set
for each force) |
The 'non-existing' field particles are playing
a role similar to that of the electric or magnetic field lines: the do not
exist, but describe how the existing real particles behave. They can also be
compared to the virtual image points produced by a concave lens (see the Optics
option). There is no source of light in the virtual image point, but the rays
of light after passing the lens act as if there was one. This virtual image
cannot be focused on a screen, and in a similar way the virtual field particles
themselves cannot be detected. But even so, the distance from a virtual image
to the lens can be calculated with the same equation as for real images. And
for virtual field particles we can calculate their mass, charge and various
quantum numbers just like for real particles - which in their interactions behave
as if a virtual particle had been exchanged
between them:

a19a
Forces and virtual exchange particles
|
ELECTROMAGN. |
STRONG/COLOR |
WEAK |
GRAVITY |
|
photon |
mesons/gluons |
vector bosons W, Z |
graviton? |
Classification of real (observed) particles
|
real |
virtual |
||
|
leptons |
quarks (as hadrons) |
[otherwise
same structure....] |
|
|
|
baryons(qqq) |
mesons(qq') |
|
Leptons
|
|
Gener. 1 |
|
Gener. 2 |
|
Gener. 3 |
|
|
Name |
electron |
el. neutrino |
muon |
mu.neutrino |
tauon |
ta.neutrino |
|
Symbol |
e |
ne |
m |
nm |
t |
nt |
|
Charge |
-1 |
0 |
-1 |
0 |
-1 |
0 |
Quarks
|
|
Gener. 1 |
|
Gener. 2 |
|
Gener. 3 |
|
|
Name |
up |
down |
strange |
charm |
bottom/beauty |
top/truth |
|
Symbol |
u |
d |
s |
c |
b |
t |
|
Charge |
+2/3 |
-1/3 |
-1/3 |
+2/3 |
-1/3 |
+2/3 |
Quark
aggregates = hadrons
Quarks
exists in two forms of hadrons (a
hadron is anything made up of quarks):
The common
proton and neutron are baryons, aggregates of three quarks:
·
proton = uud (two up-quarks and one down-quark); total charge +2/3 + 2/3
- 1/3 = +3/3 = +1 (times the elementary charge)
·
neutron = udd (one up-quark and two down-quark) total charge +2/3 - 1/3
- 1/3 = 0
The quarks exists in different
"versions" with properties assigned the term "color"; a
quark can be "red", "green" or "blue". These
terms have no relation to colours as wavelength or frequency intervals for
photons of visible light. (Photons, with no rest mass, are neither quarks nor
leptons; they are particles in some sense not enough to get a place in this
scheme. Neutrinos on the other hand, though they may be massless are leptons
(they may on the other hand have a rest mass that is very low)).
There seems
to be a rule in the universe that free particles are always colourless or
"white"; either as a baryon (red-green-blue) or as a meson which must
then be an aggregate of quarks with opposite color value (red-antired).
Isolated quarks have so far not been detected.
The strong = color force
The strong or color force is one force described
at different levels - between a proton and a neutron it is the
"strong" force keeping the atomic nucleus stable with mesons as
exchange particles. But the proton, neutron and meson are themselves made of
quarks which are kept together by the (same) "color" force, with
gluons as virtual exchange particles. So the strong interaction between the
proton and the neutron can alternatively be described as a case of color
interaction with gluons (in and between the proton, neutron and meson) as
exchange particles. There may also be particles made of only gluons
("glueballs"), but their existence is not yet confirmed.
(Compare this to the one and same
electromagnetic force which can act between to ions but at the same time
between the electrons and protons in the ion)
The weak force
This force plays a role in beta decay and is
the only force neutrinos interact with (if they are massless).
Antiparticles
To every particle there is an antiparticle
which has the same mass but opposite electric charge and other properties
(various quantum numbers, such as lepton and baryon number; momentum).
Antiparticles are "real" particles which can interact with other
materia and be detected, not virtual particles (although there can be virtual
antiparticles like there can be virtual ordinary particles).
·
Antiparticles can be produced from a very high energy photon; to conserve total
electric charge we always get both an ordinary particle and an antiparticle (pair
production). The photon must have the energy
E = hf = 2mparticlec2 = 2mantiparticlec2
·
If an antiparticle meets an "ordinary" real particle, they are
annihilated and their mass turns to energy as photons (sometimes also other
particles). Antiparticles can therefore not be stored in any ordinary container
- they would be annihilated at contact with a wall atom - but can be
temporarily contained with electromagnetic fields. Since large amounts of
energy are released in an annihilation the are used in high-energy particle
physics where various otherwise unusual (and often very short-lived) particles
are produced.
Beta
decay revised
Certain quantum numbers, such as the number of
baryons or leptons seem to be conserved in all reactions. An example of this is
the lepton number L, defined so that:
L = 1 for leptons, L = -1 for antileptons, L =
0 for others
Let us now
review the b - - decay:
AZX -> AZ+1Y + 0-1e + 00n
Before the reaction we have no leptons (in the
decaying nucleus X; there are electrons in the atomic electron shell but they
are not part of the decay proper). After the decay we have the daughter nucleus
Y (same story) and the electron (a lepton) and the antineutrino (an
antilepton). The total lepton number is therefore 0 both before and after.
Unified theories
It can be shown that the electromagnetic an
weak forces are two forms of one force, and further that this "electroweak
force" and the strong force all are the same force in "grand unified
theories" (GUT). Attempts have been made to describe all four fundamental
forces (including gravity) as one force (TOE = theory of everything) but so far
the situation is not entirely clear about this.
6.20. Accelerators
Much of the experimental particle physics is
done with accelerators, where particles are given enourmous kinetic energies
and in collisions may produce new particles. To accelerate a particle it must
be electrically charged (atoms can be accelerated as ions). Electric fields are
used to increase the speed and electric or magnetic fields to keep the
accelerated particle in the desired path. The kinetic energy received by a
particle accelerated through the potential difference (voltage) V is:
Ek = ½mv2 = qV
To reach very high kinetic energies high
voltages are used, and the voltage is used several times. Two types of
accelerators are:
·
linear accelerators, where an alternating voltage is connected to
a series of tubes so that the particle is always repelled by the previous tube
and attracted by the following. The voltage changes polarity while the particle
passes through the tube. Since the particle will travel faster and faster and
pass a given length of tube in a shorter time, they have to become longer and longer. (The sketch below
where a particle goes from a longer to a shorter tube is incorrect).
a19b
·
cyclotrons, which are based on keeping the particles in circular
paths with a magnetic field providing centripetal force. The circular motion
takes place in D-shaped half-circles with a small gap between; over this gap a
high AC voltage is applied so that they are accelerated every time they pass
the gap. The radius of the path increases, but the "cyclotron
frequency" remains the same:
a19c
Fc = Fm => mv2/r
= qvB => mv/r = qB => v = rqB/m and since v = 2pr/T = 2pf we get:
fcyclotron = qB/2pm
For very high speeds, the cyclotron frequency
needs to be adjusted during the acceleration because of relativistic effects
(this is done in a synchrocyclotron).